Answer:
The work required is -515,872.5 J
Explanation:
Work is defined in physics as the force that is applied to a body to move it from one point to another.
The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.
Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:
[tex]Ec=\frac{1}{2} *m*v^{2}[/tex]
where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).
The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:
[tex]W=\frac{1}{2} *m*v2^{2}-\frac{1}{2} *m*v1^{2}[/tex]
[tex]W=\frac{1}{2} *m*(v2^{2}-v1^{2})[/tex]
In this case:
Replacing:
[tex]W=\frac{1}{2} *2145 kg*((12\frac{m}{s} )^{2}-(25\frac{m}{s} )^{2})[/tex]
W= -515,872.5 J
The work required is -515,872.5 J
The amount of work needed by the vehicle to decrease its speed from 25 m/s to 12 m/s is 515872.5 J.
The amount of work required by the truck to decrease its speed can be calculated using the formula below.
Formula:
Where:
From the question,
Given:
Substitute these values into equation 1
Hence, The amount of work needed by the vehicle to decrease its speed from 25 m/s to 12 m/s is 515872.5 J.
Learn more about work here: brainly.com/question/18762601
