quick mathswatch ASAP Will give brainliest for the person who explains

find the equation of the straight line passing through the point of (0,1) which is perpendicular to line y=-2+2

Respuesta :

Answer:

The equation  is : x-2y+2=0.

Answer:

y = [tex]\frac{1}{2}[/tex] x + 1

Step-by-step explanation:

I'm guessing you're missing an x and the equation is: y = -2x +2, based on that:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - 2x +2 is in this form

with slope m = - 2

The slope of a perpendicular line is the negative reciprocal of m, so

[tex]-2=\frac{-2}{1}[/tex]  so the  [tex]m_{perp} = \frac{1}{2}[/tex]

(0 ,  1 ) is the y-intercept ⇒ c =  1

y = [tex]\frac{1}{2}[/tex] x + 1  ← equation of a perpendicular line