Answer:
Temperature of gas is 3.21×10² K
Explanation:
Given data:
Volume of bulb = 400 cm³ (400/1000 = 0.4L)
Pressure of bulb = 200 KPa (200/101= 1.974 atm)
Number of moles of gas = 0.03 mol
Temperature of gas = ?
Solution:
Formula:
PV = nRT
R = general gas constant = 0.0821 atm.L/ mol.K
1.974 atm × 0.4 L= 0.03 mol × 0.0821 atm.L/ mol.K × T
0.7896 atm.L = 0.002463 atm.L/K × T
T = 0.7896 atm.L / 0.002463 atm.L/K
T = 321 K 0r 3.21×10² K
