Jack's family left home at 9:00 AM and drove to the amusement park at 60 mph. They spent 7 hours at the park and then drove back home. On the way home, traffic was bad and they drove 20 mph slower than in the morning. They got home at 8:00 PM. How far is the amusement park from Jack's home?

Respuesta :

Answer:

96

Step-by-step

the distance from the amusement to jack's home is x (mile, x>0)

jack's family went to the amusement park at: 9 + x/60

On the way home, traffic was bad and they drove 20 mph slower than in the morning⇒ they drove: 60 - 20 = 40 mph

they left the amusement park at: 20 - x/40

have the following equation:

(20 - x/40) - (9+ x/60) = 7

⇔ 4 = x/40 + x/60

⇔ x = 96

so the distance from the amusement park to jack's home is 96 mile

                                         

Distance of amusement park from Jack's home = 96 miles

  • Let the distance from Jackie's house to the amusement park be x.

She drove at a speed of 60 mph to get to the amusement park.

  • Now, formula for time is;

Time = distance/speed

Time; t1 = x/60 hours

  • Now, we are told she spent 7 hours at the park. Thus; t2 = 7 hours

  • On her way back home from school, we are told she drove 20 mph slower than her speed in the morning. Thus, speed = 60 - 20 = 40 mph

Thus; time; t3 = x/40

  • Now, she left home by 9 am and got home by 8pm same day. This is a total of t = 11 hours

Thus;

t1 + t2 + t3 = 11

Plugging in the relevant values;

(x/60) + 7 + (x/40) = 11

Rearrange to get;

(x/60) + (x/40) = 11 - 7

(x/60) + (x/40) = 4

Multiply through by 120 to get

2x + 3x = 480

5x = 480

x = 480/5

x = 96 miles

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