Answer:
[tex]\left(3c-2\right)\left(6a-5\right)[/tex]
Step-by-step explanation:
[tex]18ac - 12a - 15c + 10\\\\=\left(18ac-12a\right)+\left(-15c+10\right)\\\\\mathrm{Factor\:out\:}-5\mathrm{\:from\:}-15c+10\mathrm{:\quad }-5\left(3c-2\right)\\\\\mathrm{Factor\:out\:}6a\mathrm{\:from\:}18ac-12a\mathrm{:\quad }6a\left(3c-2\right)\\\\=-5\left(3c-2\right)+6a\left(3c-2\right)\\\\\mathrm{Factor\:out\:common\:term\:}3c-2\\\\=\left(3c-2\right)\left(6a-5\right)[/tex]
