Answer:
The tiger will land at 3.71 meters from the base of the rock
Explanation:
Horizontal Motion
When an object is thrown horizontally with a speed vo from a height h, the range or maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
The tiger leaps from a height of h=7.5 m with a speed of v=3 m/s. Substituting the values into the formula:
[tex]\displaystyle d=3\cdot\sqrt{\frac {2\cdot 7.5}{9.8}}=3.71\ m[/tex]
The tiger will land at 3.71 meters from the base of the rock
