nubianqueen333
contestada

What is the acceleration of a mongoose that, if from rest, can reach
speeds of 19 ft/s in 8.8 seconds?
O 2.25 s
O 174.24 ft/s/s
2.25 ft/s/s
2.25 m/s

Respuesta :

MathPhys

Explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

a = (19 ft/s − 0 ft/s) / 8.8 s

a = 2.16 ft/s/s

quasarJose

Given parameters:

Initial velocity  = 0m/s

Final velocity = 19ft/s

Time taken  = 8.8s

Unknown:

Acceleration

Solution:

Acceleration is the change in velocity with time of a body;

                 Acceleration  = [tex]\frac{v - u}{t}[/tex]

v is the final velocity

u is the initial velocity

t is the time taken

    input the parameters and solve;

              Acceleration = [tex]\frac{19 - 0}{8.8}[/tex]  = 2.16ft/s

Now, the acceleration is 2.16ft/s

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