Answer:
[tex]4y = 16-2x\\y = \frac{16}{4} - \frac{2x}{4}\\ y = \frac{-1x}{2}+4\\y = 0.5x+4[/tex]
Given parameters:
Equation of the straight line;
2x + 4y = 16
The slope intercept form of the equation is y = mx + c
Where m is the slope of the line
y and x are the coordinates
c is the intercept
So, the problem is to write the given equation in form of y = mx + c;
2x + 4y = 16
4y = 16 - 2x
Divide through by 2;
[tex]\frac{4y}{2}[/tex] = [tex]\frac{16}{2}[/tex] - [tex]\frac{2x}{2}[/tex]
2y = 8 - x
2y = -x + 8
Then divide by 2 all through;
[tex]\frac{2y}{2}[/tex] = [tex]\frac{-x}{2} + \frac{8}{2}[/tex]
y = [tex]\frac{-x}{2} + 4[/tex]
The equation of the line is y = [tex]\frac{-x}{2} + 4[/tex]
