Answer:
C = - 8
Step-by-step explanation:
[tex]f(x) = \frac{3}{2} x + c \\ \\ plug \: x = 6 \\ \\ f(6) = \frac{3}{2} \times 6 + c \\ \\ f(6) = 3 \times 3 + c \\ \\ f(6) = 9+ c \\ \\ \therefore \: 1 = 9 + c \: \{ \because \: f(6) = 1 \} \\ \\ 1 - 9 = c \\ \\ \huge \red{ \boxed{ c = - 8}}\\\\
f(c) =\frac{3}{2} c +(-8)\\\\
\huge \orange { \boxed{ f(c) =\frac{3}{2} c -8}} \\\\ [/tex]
