please help urgent!!
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Answer:
The area of the rectangle is [tex]A=12b^6+6b^3-18b^2[/tex]
Step-by-step explanation:
Area of a rectangle
A rectangle of height H and width W has an area of:
[tex]A=H*W[/tex]
The rectangle shown in the figure has a height of:
[tex]H=3b^2[/tex]
And a width of
[tex]W=4b^4+2b-6[/tex]
The area is
[tex]A=(3b^2)(4b^4+2b-6)[/tex]
Operating:
[tex]A=(3b^2)*4b^4+(3b^2)*2b-(3b^2)6[/tex]
[tex]A=12b^6+6b^3-18b^2[/tex]
The area of the rectangle is [tex]A=12b^6+6b^3-18b^2[/tex]