Respuesta :

Answer:

The area of the rectangle is [tex]A=12b^6+6b^3-18b^2[/tex]

Step-by-step explanation:

Area of a rectangle

A rectangle of height H and width W has an area of:

[tex]A=H*W[/tex]

The rectangle shown in the figure has a height of:

[tex]H=3b^2[/tex]

And a width of

[tex]W=4b^4+2b-6[/tex]

The area is

[tex]A=(3b^2)(4b^4+2b-6)[/tex]

Operating:

[tex]A=(3b^2)*4b^4+(3b^2)*2b-(3b^2)6[/tex]

[tex]A=12b^6+6b^3-18b^2[/tex]

The area of the rectangle is [tex]A=12b^6+6b^3-18b^2[/tex]