Answer:
Na₂SO₄·10H₂O.
Explanation:
Hello.
In this case, since the anhydrous sodium sulfate is:
[tex]Na_2SO_4[/tex]
Whose molar mass is:
[tex]M=23+32+16*4=142 g/mol[/tex]
But the total hydrate's molar mass is 322.1 g/mol, we can compute the mass of water:
[tex]m_{water}=322.1-142=180.1g/mol[/tex]
Thus, the molecules of water are found by diving the total mass of water by the mass of one mole of water:
[tex]#water=\frac{180.1}{18}=10[/tex]
It means, that the formula is Na₂SO₄·10H₂O.
Best regards.
