Answer:
118 g of Ar; 28.8 g of [tex]NO_{2}[/tex]
Explanation:
To convert from moles to grams, you simply multiply by the atomic mass. So the conversion table looks as follows:
[tex]\frac{2.95 mol}{1} *\frac{39.95 g}{1 mol}[/tex]
The mol units cancel, and you are left with 118 g of Argon (117.8525 without sig-figs).
As for the next part of our problem, the first thing we need to do is find the molar mass of [tex]NO_{2}[/tex]. e can do this by adding the weight of all the atoms within the compound:
N + 2(O) = (14.01) + 2(16) = 46.01 g
Then, we repeat the above process, except we use the molar mass we just found instead of the atomic weight:
[tex]\frac{0.627 mol}{1}*\frac{46.01 g}{1 mol}[/tex]
Once again, the mol units cancel, and we are left with 28.8 g of [tex]NO_{2}[/tex] (28.84827 before sig-figs).
