Answer:
The mass of oxygen gas is 0.96 g.
Explanation:
Given data:
Mass of oxygen gas = ?
Volume of as = 320 mL (320mL × 1L /1000 mL = 0.32 L)
Temperature of gas = 17 °C
Pressure of gas = 2 atm
Solution:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
17+273 = 290 K
Now we will put the values in formula.
2 atm × 0.32 L = n × 0.0821 atm.L/ mol.K × 290 K
0.64 atm.L = n × 23.81 atm.L/ mol.
n = 0.64 atm.L / 23.81 atm.L/ mol.
n = 0.03 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 0.03 mol × 32 g/mol
Mass = 0.96 g
The mass of oxygen gas is 0.96 g.
The mass of oxygen will be "0.96 g".
Given:
Volume,
or,
= 0.32 L
Temperature,
or,
= 290 K
Pressure,
General gas constant,
As we know the formula,
→ [tex]PV = nRT[/tex]
By substituting the values, we get
[tex]2\times 0.32=n\times 0.0821\times 290[/tex]
[tex]0.64=n\times 23.81[/tex]
[tex]n = \frac{0.64}{23.81}[/tex]
[tex]= 0.03 \ mol[/tex]
hence,
→ Mass of oxygen = [tex]Number \ of \ moles\times Molar \ mass[/tex]
= [tex]0.03\times 32[/tex]
= [tex]0.96 \ g[/tex]
Thus the above answer is right.
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