Answer:
Modification has not reduced the number of accidents.
Step-by-step explanation:
[tex]H_0: \mu\geq0\\H_a:\mu <0[/tex]
A B C D E F G H
Before modification 5 7 6 4 8 9 8 10
After modification 3 7 7 0 4 6 8 2
Difference -2 0 1 -4 -4 -3 0 -8
Mean of differences [tex]M_d = \frac{sum}{8}=\frac{2+0-1+4+4+3-0+8}{8}=2.5[/tex]
Standard deviation of differences = [tex]\sqrt{\frac{\sum(x-\bar{x})^2}{n}}=2.9277[/tex]
Formula of paired t test :
[tex]t=\frac{M_d}{\frac{s}{\sqrt{n}}}\\t=\frac{2.5}{\frac{2.9277}{\sqrt{8}}}\\t = 2.4152[/tex]
Df = n-1 = 8-1 =7
[tex]t critical = t_{(df, \alpha)}=t_{7,0.01}=2.998[/tex]
t critical> t calculated
So, We failed to reject null hypothesis
Hence modification has not reduced the number of accidents.