Answer:
The value is [tex]q = 70.8\ C[/tex]
Explanation:
From the question we are told that
The area is [tex]A = 2.0 \ k m^2 = 2000000 \ m[/tex]
The height is [tex]h = 10 \ km = 10000 \ m[/tex]
The electric field is [tex]E = 4.0*10^{6} \ N/C[/tex]
Generally the electric field is mathematically represented as
[tex]E = \frac{q}{A * \epsilon_o }[/tex]
Here [tex]\epsilon_o }[/tex] is the permitivity of free space with value
[tex]\epsilon_o } = 8.85 *10^{-12} \ N \ m^2 /C^2[/tex]
=> [tex]4.0*10^{6} = \frac{q}{2000000 * 8.85 *10^{-12} }[/tex]
=> [tex]q = 70.8\ C[/tex]