Answer:
a = 0 m/s²
T = 2m₂g
Explanation:
In this scenario of a pulley with two masses hanging vertically over it, the formula of acceleration is given as follows:
a = g(m₁ - m₂)/(m₁ + m₂)
It is given that: m₁ = m₂ = m
Therefore,
a = g(m - m)/(m + m)
a = g(0)/(2m)
a = 0 m/s²
The tension of the rope in such case is given by the following formula:
T = 2m₁m₂g/(m₁ + m₂)
It is given that: m₁ = ∞
Therefore,
T = 2(∞)m₂g/(∞ + m₂)
T = ∞(2m₂g)/∞(1 + m₂/∞)
T = 2m₂g/(1 + 0)
T = 2m₂g
