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HELP PLZ!!! A sample contains only the compound CaCl2 and water. When it is dried, its weight decreases from 5.00g to 4.24g. What is the mass percentage of water in the original sample? Round to three significant figures.

Respuesta :

Answer:is 15.2%

Explanation:

Got it wrong and this the correct answer it told me

pstnonsonjoku

The percentage of water in the original sample is 15.2 %.

From the information provided in the question;

Weight of the wet sample = 5.00g

Weight of the dried sample = 4.24g

Loss in mass =  5.00g - 4.24g = 0.76 g

percentage of water in the original sample = Difference in mass between wet and dry sample/ mass of wet sample × 100/1

Hence, when we substitute values;

percentage of water in the original sample =  0.76 g/5.00g × 100/1

percentage of water in the original sample = 15.2 %

So, the percentage of water in the original sample is 15.2 %.

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