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The lengths of pregnancies in a small rural village are normally distributed with a mean of 260 days and a standard deviation of 17 days.

In what range would you expect to find the middle 98% of most pregnancies?

Respuesta :

mberisso

Answer:

Rounded to the nearest  integer the range would be:

220 < x < 300

Step-by-step explanation:

For a 98%the Z-score is 2.326

then you calculate the interval using:

Mean +/- Z * standard deviation

In our case:

260 +/- 2.326 * 17 = between     220.458 and 299.542

Rounded to the nearest  integer would be:

220 < x < 300