Graphically determine the slopes of the line segments that create triangle ACD shown below. Write your final slopes in simplest form.
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Answer:
Step-by-step explanation:
From the graph attached,
Coordinates of points A, C and D are,
A(-2, -7), C(-6, 7) and D(9, 2)
Slope of AD = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{-7-2}{-2-9}[/tex]
= [tex]\frac{9}{11}[/tex]
Slope of CD = [tex]\frac{7-2}{-6-9}[/tex]
= [tex]-\frac{1}{3}[/tex]
Slope of AC = [tex]\frac{7-(-7)}{-6-(-2)}[/tex]
= [tex]-\frac{14}{4}[/tex]
= [tex]-\frac{7}{2}[/tex]
The slope of a line segment AD is 9/11, the slope of a line segment CD is -1/3, and the slope of a line segment AC is -7/2.
Given :
a) The slope of a line segment AD is calculated as:
[tex]\rm m = \dfrac{2+7}{9+2}[/tex]
m = 9/11
b) The slope of a line segment CD is calculated as:
[tex]\rm m = \dfrac{2-7}{9+6}[/tex]
m = -1/3
c) The slope of a line segment AC is calculated as:
[tex]\rm m = \dfrac{7+7}{-6+2}[/tex]
m = -7/2
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https://brainly.com/question/3605446