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The figure shows two springs (k1 = 10 N/m and k2 = 20 N/m ) attached to a block that can slide on a frictionless surface. In the block's equilibrium position, the left spring is compressed by x1 = 2.0 cm.
a) By how much is the right spring compressed?
b) What is the net force on the block if it is moved 14 cm to the right of its equilibrium position?

The figure shows two springs k1 10 Nm and k2 20 Nm attached to a block that can slide on a frictionless surface In the blocks equilibrium position the left spri class=

Respuesta :

Answer:

Explanation:

a )

Energy stored by left spring when compressed = 1/2 k x²

= .5 x 10 x .02² = .002 J .

Let compression in right spring = y

energy stored to right spring = 1/2 k y²

1/2 k y² = 0.002

.5 x 20 x y² = 0.002

y = .01414 m

= 1.4  cm

poona2339

Energy stored by left spring when compressed = 1/2 k x²

= .5 x 10 x .02² = .002 J .

Let compression in right spring = y

energy stored to right spring = 1/2 k y²

1/2 k y² = 0.002

.5 x 20 x y² = 0.002

y = .01414 m

= 1.4  cm

What does compression mean in Earth Science?

  • Tensional
  • Compressional
  • Sheer

Should I use compression?

  • Fighting off infections in your body
  • Reducing water retention
  • Promoting weight loss
  • Reducing swelling
  • Healthier pores
  • Healing scar tissue and stretch marks
  • Reducing cellulite

Learn more about compression here https://brainly.com/question/14828391

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