Use the quadratic formula to find the solutions to the equation.
3x2 - 10x + 5 = 0
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Answer: A
Step-by-step explanation:
3x² - 10x + 5 = 0
a = 3 b = -10 c = 5
Δ = b²- 4ac = 100 - 4.3.5 = 40 > 0 => have 2 solutions
=> x = [tex]\frac{10+\sqrt{40} }{6}[/tex] or x = [tex]\frac{10-\sqrt{40} }{6}[/tex]
[tex]x= \frac{10\pm \sqrt{40} }{6}[/tex] is the solution to the given quadratic equation.
Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = [tex]ax^{2} +bx+c[/tex] = 0 where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where 'a' is called the leading coefficient and 'c' is called the absolute term of f (x).
Quadratic formula = [tex]\frac{-b\pm \sqrt{b^{2} -4ac} }{2a}[/tex]
Given quadratic equation
[tex]3x^{2} -10x+5=0[/tex]
a = 3, b = -10, c = 5
Quadratic formula = [tex]\frac{-b\pm \sqrt{b^{2} -4ac} }{2a}[/tex]
[tex]x= \frac{-(-10)\pm \sqrt{(-10)^{2} -4(3)(5)} }{2\times3}[/tex]
⇒ [tex]x= \frac{10\pm \sqrt{100 -60} }{6}[/tex]
⇒ [tex]x= \frac{10\pm \sqrt{40} }{6}[/tex]
Hence, [tex]x= \frac{10\pm \sqrt{40} }{6}[/tex] is the solution to the given quadratic equation.
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