Answer:
2.79 x 10²³atoms
Explanation:
Given parameters:
Mass of N₂O₅ = 25g
Unknown:
Number of atoms of Nitrogen present = ?
Solution:
To solve this problem, it is best to find the number of moles of nitrogen present in the sample first.
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of N₂O₅ = 2(14) + 5(16) = 108g/mol
Number of moles = [tex]\frac{25}{108}[/tex] = 0.23mol
1 mole of N₂O₅ contains 2 mole of N
0.23 mole of N₂O₅ will contain 0.23 x 2 = 0.46mole of N
1 mole of a substance = 6.02 x 10²³ atoms
0.46 mole of nitrogen = 0.46 x 6.02 x 10²³ atoms = 2.79 x 10²³atoms
