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The pressure inside a sealed container of methane gas (CH4) is 35.0 kPa. If this 80.0 L sample
of methane is increased to a pressure of 92.0 kPa, what is the new volume?

Respuesta :

Stephen46

Answer:

The answer is 30.43 L

Explanation:

The new volume can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we are finding the new volume

[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]

From the question we have

[tex]V_2 = \frac{35000 \times 80}{92000} = \frac{2800000}{92000} = \frac{700}{23} \\ = 30.434782...[/tex]

We have the final answer as

30.43 L

Hope this helps you

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