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Answer: Find the equation of the line that passes through the points (-6,2) and (-5,3). Write your answer in standrard form. Answer by fractalier(6550) ...
Step-by-step explanation:
First you would want to find the slope. The equation for slope is y2-y1/x2-x1.
So the slope would be 5-3/ 6-(-4). Two negatives make a positive so it would be 5-3/6+4 or 2/10 which can be simplified to 1/2.
Next you used the point slope form equation. y-y1 =m(x-x1)
m is the slope we just found: 1/2
the equation would be = y-3=1/2(x-(-4))
two negatives make a positive so the equation would now be y-3=1/2(x+4)
You then distribute the x to what is in the parenthesis
y-3=1/2x+2
then add the 3 to both sides
you’re equation should be y=1/2+5
So the slope would be 5-3/ 6-(-4). Two negatives make a positive so it would be 5-3/6+4 or 2/10 which can be simplified to 1/2.
Next you used the point slope form equation. y-y1 =m(x-x1)
m is the slope we just found: 1/2
the equation would be = y-3=1/2(x-(-4))
two negatives make a positive so the equation would now be y-3=1/2(x+4)
You then distribute the x to what is in the parenthesis
y-3=1/2x+2
then add the 3 to both sides
you’re equation should be y=1/2+5
