Respuesta :
[tex]\rm H_2O[/tex] has higher boiling point than [tex]\rm H_2S[/tex], as there has been stronger hydrogen bonding in [tex]\rm H_2O[/tex]. Thus, option 2 is correct.
The boiling point has been the temperature at which the liquid has been converted to the gaseous form. The boiling point has been based on the intemolecular attractions between the atoms.
Higher boiling point
Based on the intermolecular interactions, the compound with higher intermolecular force required more energy to break the bond and change the state, and thus have high boiling point.
The hydrogen sulfide and water has hydrogen bonding. The hydrogen bonding has been based on the electronegativity of the atom involved. The more electronegative atom, stronger will be hydrogen bonding and thereby higher boiling point.
In [tex]\rm H_2S[/tex] and [tex]\rm H_2O[/tex], the oxygen has been more electronegative than sulfur and thus results in stronger hydrogen bonding.
Thus, [tex]\rm H_2O[/tex] has higher boiling point than [tex]\rm H_2S[/tex], as there has been stronger hydrogen bonding in [tex]\rm H_2O[/tex]. Thus, option 2 is correct.
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