Answer:
[tex] \angle A \cong \angle D [/tex]
Step-by-step explanation:
Two ∆s can be considered to be congruent to each other using the Side-Angle-Side Congruence Theorem, if an included angle, and two sides of a ∆ are congruent to an included angle and two corresponding sides of another ∆.
∆ABC and ∆DEF has been drawn as shown in the attachment below.
We are given that [tex] \overline{AB} \cong \overline{DE} [/tex] and also [tex] \overline{AC} \cong \overline{DF} [/tex].
In order to prove that ∆ABC [tex] \cong [/tex] ∆DEF using the Side-Angle-Side Congruence Theorem, an included angle which lies between two known side must be made know in each given ∆s, which must be congruent accordingly to each other.
The included angle has been shown in the ∆s drawn in the diagram attached below.
Therefore, the additional information that would be need is:
[tex] \angle A \cong \angle D [/tex]
