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Find three consecutive integers such that the sum of twice the second and four times the third is twenty-five more than the first?

Respuesta :

joshlind3

Answer:

3, 4, 5

Step-by-step explanation:

Three consecutive integers means that

[tex]X_1, X_2 = X_1 + 1, X_3 = X_2 + 1[/tex]

The sum of twice the second and 4 times the third is 25 times the first number

[tex]X_1 + 25 = 2X_2 + 4X_3\\X_1 + 25 = 2(X_1 + 1) + 4(X_1 + 2)\\X_1 + 25 = 2X_1 + 2 + 4X_1 + 8\\X_1 + 25= 6X_1 + 10\\5X_1 = 15\\X_1 = 3\\X_2 = 4, \\X_3 = 5[/tex]

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