Respuesta :

Mass of NaOH = 45g
Mr of NaOH = (23.0+16+1) =40
Moles of NaOH = mass/Mr
= 45/40 = 1.125mol


250ml = 250cm^3
250cm^3/1000 = 0.25dm^3
Concentration = moles/volume
= 1.125/0.25
= 4.5 mol/dm^3

Hope that helps and please correct me if I’m wrong.
Eduard22sly

The molarity of the solution formed by dissolving 45 g of NaOH in water to give a final volume of 250 mL is 4.5 M

We'll begin by calculating the number of mole in 45 g of NaOH. This can be obtained as follow:

Mass of NaOH = 45 g

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Mole of NaOH =?

Mole = mass / molar mass

Mole of NaOH = 45 / 40

Mole of NaOH = 1.125 mole

  • Finally, we shall determine the molarity of the solution. This can be obtained as follow:

Mole of NaOH = 1.125 mole

Volume = 250 mL = 250 / 1000 = 0.25 L

Molarity =?

Molarity = 1.125 / 0.25

Molarity = 4.5 M

Therefore, the molarity of the solution is 4.5 M

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