Answer:
[tex]\huge\boxed{P(2;\ -3);\ Q(4;\ -2)\ \text{and}\ R(-4;\ 8)}[/tex]
Step-by-step explanation:
[tex]A(x;\ y)\xrightarrow{S_{OY}}A'(-x;\ y)\\\\\text{The abscissa changes to the opposite:}\ x\to -x\\\\\text{Therefore}\\\\P(-2;\ -3)\xrightarrow{S_{OY}}P'(2;\ -3)\\\\Q(-4;\ -2)\xrightarrow{S_{OY}}Q'(4;\ -2)\\\\R(4;\ 8)\xrightarrow{S_{OY}}R'(-4;\ 8)[/tex]