Answer:
f(x, y) = yx²/2 + 3x² + 4yx + 24x + K
Step-by-step explanation:
Given the expression dy/dx=xy+6x+4y+24
To find the solution, we are to make y the subject of the formula as shown
dy = (xy+6x+4y+24)dx
∫dy =∫(xy+6x+4y+24)dx
y = ∫(xy+6x+4y+24)dx
We are to integrate the function with respect to x keeping y constant. Since all constant are brought out if integral sign we will have;
y = ∫(xy)dx + ∫(6x)dx + ∫(4y)dx + ∫24dx
y = y∫xdx + 6∫xdx + 4y∫dx + 24∫dx
Integrate;
y = yx²/2 + 6x²/2 + 4yx + 24x + K
y = yx²/2 + 3x² + 4yx + 24x + K
Hence the solution to the differential expression is;
f(x, y) = yx²/2 + 3x² + 4yx + 24x + K
Where K is the constant of integration.
