Answer:
See Explanation
Step-by-step explanation:
Given
Rectangle A:
[tex]Length: 10\ in[/tex]
[tex]Width: 8\ in[/tex]
Required
Determine the possible dimensions of Rectangle B
The question has missing options; however, the question can still be solved.
Rectangle B being an enlarged copy of A implies that the dimension of A A is enlarged in equal proportion to form B
Take for instance, the measurements of Rectangle B are
[tex]Length: 15 in[/tex]
[tex]Width: 12 in[/tex]
Divide the corresponding lengths of B by A to get the enlargement ratio
[tex]Ratio = \frac{B}{A}[/tex]
For length:
[tex]Ratio = \frac{15}{10}[/tex]
[tex]Ratio = 1.5[/tex]
For width
[tex]Ratio = \frac{12}{8}[/tex]
[tex]Ratio = 1.5[/tex]
Notice that both ratios are the same.
For this measurement of B, we can conclude that B is an enlargement of A
Assume another measurements for B
[tex]Length: 20\ in[/tex]
[tex]Width: 10\ in[/tex]
Calculate Ratios
[tex]Ratio = \frac{B}{A}[/tex]
For length:
[tex]Ratio = \frac{20}{10}[/tex]
[tex]Ratio = 2[/tex]
For width
[tex]Ratio = \frac{10}{8}[/tex]
[tex]Ratio = 1.25[/tex]
Notice that, both ratios are not equal.
For this measurement of B, we can conclude that B is not an enlargement of A
Conclusively, all you have to do is: determine the ratios of the dimensions of B to A, if the result are equal then B is an enlarged copy of A; if otherwise, then B is not an enlarged copy
