In the diagram below, a 10-kilogram ball is fired with a
velocity of 500 meters per second from a 1,000 kilogram
cannon. What is the recoil velocity of the cannon?

A. 5 m/s
B. B) 2 m/s
C. C) 10 m/s
D. D) 500 m/s

Respuesta :

cairde

Answer:

A) 5m/s

Explanation:

Momentum of ball in one direction=momentum of cannon in other direction

mv = mv

(10)(500)=(1000)v

5000=1000v

∴v=5m/s

When a ball is fired with a velocity its momentum remains conserved. The recoil velocity of the cannon is 5m/s.


What is recoil velocity?

The velocity with which the cannon is pushed backwards after firing is called the recoil velocity.

The momentum remains conserved . So, according to the momentum conservation principle, initial momentum is equal to the final momentum.

Mu +mu=Mv +mv

where, M is the mass of cannon and m is the mass of ball.

u is the initial velocity and v is the final velocity.

10 kg ball is fired with a velocity of 500 meters per second from a 1,000 kg cannon.

mu = Mv

(10)(500)=(1000)v

5000=1000v

v=5m/s

Thus, the recoil velocity of the cannon is 5 m/s.

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