Point S is on line segment \overline{RT} RT . Given RT=4x,RT=4x, ST=5x-10,ST=5x−10, and RS=6,RS=6, determine the numerical length of \overline{ST}. ST .

Respuesta :

Answer:

[tex]ST = 10[/tex]

Step-by-step explanation:

Given

[tex]RT =4x[/tex]

[tex]ST = 5x - 10[/tex]

[tex]RS = 6[/tex]

Required

Determine ST

Since S is on RT, we have that:

[tex]RT = RS + ST[/tex]

[tex]4x = 5x - 10 + 6[/tex]

[tex]4x = 5x - 4[/tex]

[tex]4x - 5x= - 4[/tex]

[tex]-x= - 4[/tex]

[tex]x= 4[/tex]

Substitute 4 for x in [tex]ST = 5x - 10[/tex]

[tex]ST = 5 * 4 - 10[/tex]

[tex]ST = 20 - 10[/tex]

[tex]ST = 10[/tex]

Answer: It Equals 8

Step-by-step explanation:

Point S is on line segment \overline{RT}

RT

. Given ST=5x-7,ST=5x−7, RT=4x+9,RT=4x+9, and RS=2x+7,RS=2x+7, determine the numerical length of \overline{ST}.

ST

.

\text{Label known information:}

Label known information:

R

S

T

2x + 7

5x – 7

RT = 4x + 9

RS+ST=

RT

Segment addition postulate

\color{darkgreen}{2x+7}+\color{darkblue}{5x-7}=

2x+7+5x−7=

\,\,\color{darkred}{4x+9}

4x+9

Substitute expressions

7x=

7x=

\,\,4x+9

4x+9

Combine like terms

-4x\phantom{=}

−4x=

\,\,-4x

−4x

3x=

3x=

\,\,9

9

\frac{3x}{3}=

3

3x

=

\,\,\frac{9}{3}

3

9

Divide by 33

x=

x=

\,\,\color{darkgreen}{3}

3

\text{Plug in value of }x\text{ to find }ST\text{:}

Plug in value of x to find ST:

ST=5x-7=5\left(\color{darkgreen}{3}\right)-7=8

ST=5x−7=5(3)−7=8

\text{You can plug }x\text{ into each expression:}

You can plug x into each expression:

Optional to check work

R

S

T

2(3) + 7

5(3) – 7

RT = 4(3) + 9

\text{Simplify:}

Simplify:

R

S

T

13

8

RT = 21

\text{Final Answer:}

Final Answer:

ST=\color{green}{\mathbf{8}}

ST=8