Answer:
0.603
Step-by-step explanation:
Given that mean = 3.2
Probability that special order sent out will be no more than 3
Using poisson :
P(x) = (e^λ * λ^x) / x!
λ= 3.2
P(x≤3) : = p(x = 0) + p(x = 1) + p(x= 2) + p(x =3)
P(x = 0) = (e^-3.2 * 3.2^0) / 0! = 0.0407622
P(x = 1) = (e^-3.2 * 3.2^1) / 1! = 0.1304390
P(x = 2) = (e^-3.2 * 3.2^2) / 2 = 0.2087024
P(x = 3) = (e^-3.2 * 3.2^3) / 3! = 0.2226159
Hence ;
0.0407622 +0.1304390 + 0.2087024 + 0.2226159 = 0.6025195
= 0.603
