Answer:
[tex]\%m/m=14\%[/tex]
Explanation:
Hello!
In this case, since the molarity of magnesium chloride (molar mass = 95.211 g/mol) is 1.672 mol/L and we know the density of the solution, we can first compute the concentration in g/L as shown below:
[tex][MgCl_2]=1.672\frac{molMgCl_2}{L}*\frac{95.211gMgCl_2}{1molMgCl_2}=159.2\frac{gMgCl_2}{L}[/tex]
Next, since the density of the solution is 1.137 g/mL, we can compute the concentration in g/g as shown below:
[tex][MgCl_2]=159.2\frac{gMgCl_2}{L}*\frac{1L}{1000mL}*\frac{1mL}{1.137g}=0.14[/tex]
Which is also the by-mass fraction and in percent it turns out:
[tex]\%m/m=0.14*100\%\\\\\%m/m=14\%[/tex]
Best regards!
