contestada

Major league baseball salaries averaged $3.26 million with a standard deviation of $1.2 million in a certain year in the past. Suppose a sample of 100 major league players was taken. The probability that the mean salary of the 100 players exceeded $3.26 million is:________a. 0.0228b. 0.9772c. approximately 1d. approximately 0

Respuesta :

Answer:

b) 0.0228

Step-by-step explanation:

We use the z score formula when given random number of samples =

z = (x-μ)/σ/√n where

x is the raw score = $3.5 million

μ is the population mean = $3.26 million

σ is the population standard deviation = $ 1.2 million

n = random number samples = 100

Hence,

z = 3.5 - 32.6/1.2/√100

z = 3.5 - 32.6/1.2/10

z = 3.5 - 3.26/0.12

z =2

Probability value from Z-Table:

P(x<3.5) = 0.97725

P(x>3.5) = 1 - P(x<3.5)

P(x>3.5) = 1 - 0.97725

P(x > 3.5) = 0.02275

Approximately ≈ 0.02278

The approximate probability that the mean salary of the 100 players exceeded $3.5 million is 0.02278

Otras preguntas