Answer:
Equation in slope-intercept form that goes through (12, 4) and (20,8) is: [tex]y = \frac{1}{2}x-2[/tex]
Step-by-step explanation:
Given two points are:
[tex](x_1,y_1) = (12,4)\\(x_2,y_2) = (20,8)[/tex]
Slope intercept form of line is given as:
[tex]y = mx+b[/tex]
Here m is the slope of the line and b is the y-intercept.
Slope of a line is calculated by the formula:
[tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]
Putting the values
[tex]m = \frac{8-4}{20-12}\\m = \frac{4}{8}\\m=\frac{1}{2}[/tex]
Putting the value of slope in slope-intercept form we get
[tex]y = \frac{1}{2}x+b[/tex]
To find the value of b, any one point will be put in the equation
Putting the first point (12,4) in the equation
[tex]4 = \frac{1}{2}(12) + b\\4 = 6+b\\b = 4-6\\b = -2[/tex]
Putting the value of b
[tex]y = \frac{1}{2}x-2[/tex]
Hence,
Equation in slope-intercept form that goes through (12, 4) and (20,8) is: [tex]y = \frac{1}{2}x-2[/tex]
