Given log3 4 = 1.262 and log3 7 = 1.771, what is the value of log3 (7/16)?
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Answer:
[tex]log_3(\frac{7}{16}) =-0.753[/tex]
Step-by-step explanation:
Use the laws of log()
[tex]log_x(\frac{a}{b}) =log_x(a)-log_x(b)[/tex]
[tex]log_3(\frac{7}{16}) =log_3(7)-log_3(16)[/tex]
[tex]log_3(\frac{7}{16}) =log_3(7)-log_3(4^2)[/tex] you can move exponent outside of log()
[tex]log_3(\frac{7}{16}) =log_3(7)-2log_3(4)[/tex]
[tex]log_3(\frac{7}{16}) =(1.771)-2(1.262)[/tex]
[tex]log_3(\frac{7}{16}) =-0.753[/tex]