We have a jumper that jumps from 1500ft above the ground, such that its height as a function of time is given by:
h(t) = -16*t^2 + 1500
The solutions are:
A) 5.59 seconds
B) 5.91 seconds
C) D = (0s, 9.68s)
R = [0ft, 1500ft]
Notice that when t = 0, h = 1500, then at the initial time (t = 0) the height is 1500 (in ft), which means that the zero of the height is the ground.
a) How long is the jumper free fall if the parachute opens at 1000 ft?
Here we need to solve:
h = 1000 = -16*t^2 + 1500
Now we just need to solve this for t:
16*t^2 = 1500 - 1000 = 500
t^2 = 500/16 = 31.25
t = √31.25 = 5.59
So it takes 5.59 seconds to open the parachute.
B) similar to before, this time we need to solve:
h = 940 = -16*t^2 + 1500
16*t^2 =1500 - 940 = 560
t^2 = 560/16 = 35
t = √35 = 5.91
So it takes 5.91 seconds to open the parachute.
C) The domain is the set of inputs that we can use in the function.
The minimum of the domain is t = 0, when the jumper jumps.
To find the maximum of the domain we need to find the maximum time at which he could open the parachute, that is when h = 0ft, just in the ground.
Then we solve:
h = 0 = -16*t^2 + 1500
16*t^2 = 1500
t = √(1500/16) = 9.68
Then a reasonable domain is (0s, 9.68s)
And the range is the set of possible outputs, which will be all the possible heights of the jumper. We know that all of these are between 0ft and 1500ft, thus the range is [0ft, 1500ft]
If you want to learn more, you can read:
https://brainly.com/question/1632425
