Answer:
Assuming it is a constant function.
[tex]f(x)=0x-2[/tex]
Step-by-step explanation:
(5,-2)
(-6,-2)
(3,-2)
(4,-2)
From the points, we can see that for any value of [tex]x[/tex], the function will give -2. The graph of this function will be a horizontal line, parallel to the [tex]x[/tex]-line passing the y-intersect point -2.
So the function might be
[tex]f(x)=0x-2[/tex]
If it is a constant function.
I'm considering that there are no discontinuities.
