Respuesta :
Answer:
The gravitational force on the elevator = 4500N
Explanation:
The given parameters are;
The force applied by the elevator, F = 4500 N
The acceleration of the elevator = Not accelerating
From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows;
F = W + Mass of elevator × Acceleration of elevator
∴ F = W + Mass of elevator × 0 = W
F = 4500 N = W
The net force on the elevator is F - W = 0
The gravitational force on the elevator = W = 4500N.
The gravitational force on the elevator, if the elevator is NOT accelerating is 4500 N.
Given data:
The magnitude of force on the elevator is, F = 4500 N.
From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows,
F = W + ma
Here, a is the acceleration of the elevator. Since, the elevator is not accelerating. Then, a = 0 .
The weight of the elevator is due to the gravitational force. So, we need to obtain the weight as gravitational force.
Solving as,
[tex]F = W+ma\\\\F=W +(m \times 0)\\\\4500=W\\\\W = 4500 \;\rm N[/tex]
Thus, we can conclude that the gravitational force on the elevator, if the elevator is NOT accelerating is 4500 N.
Learn more Newton's third law here:
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