(a) The distance will be "6.282 cm".
(b) Mass will be "2.03 kg".
(a)
From Archimedes' principle, we get
→ [tex]L^3 \rho_{Wood} = L^2 d \rho_{Water}[/tex]
[tex]d = L \frac{\rho_{Wood}}{\rho_{Water}}[/tex]
[tex]= 18\times \frac{651}{1000}[/tex]
[tex]= 11.72 \ cm[/tex]
So,
The distance from horizontal top to the water level will be:
= [tex]18-11.72[/tex]
= [tex]6.282 \ cm[/tex]
(b)
After placing the lead block of weight [tex]W_L[/tex], we have
→ [tex]W_L +L^3 \rho_{Wood} g = L_3 \rho_{Water} g[/tex]
[tex]W_L = L^3 g(\rho_{Water}-\rho_{Wood})[/tex]
[tex]= 0.18^3\times 9.8\times (1000-651)[/tex]
[tex]= 19.94 \ N[/tex]
Mass,
m = 2.03 kg
Thus the above answer is right.
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