What is the length of EF in the right triangle below? E 39 A D 15 F
A. 585
B. 576
C. 1296 D. 24
E. 36
F. 54
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Answer:
E. 36
Step-by-step explanation:
You have to do a² + b² = c²
Plug in
15² + b² = 39²
225 + b² = 1521 (subtract 225 on both sides)
√b² = √1296 (square root on both sides)
b = 36
Hope this helps ya!
The length of the EF in the right-angle triangle is 36 units if the length of DF is 15 units the length of DE is 39 units option (E) is correct.
It is a triangle in which one of the angles is 90 degrees and the other two are sharp angles. The sides of a right-angled triangle are known as the hypotenuse, perpendicular, and base.
We have a right angle triangle shown in the picture.
The length of DF = 15 units
The length of DE = 39 units
As we know, Pythagoras' theorem can be defined as the square of the hypotenuse in a right-angled triangle equal to the sum of the squares of the other two sides.
Applying Pythagoras theorem:
DE² = DF² + EF²
Plug the known values:
39² = 15² + EF²
1521 = 225 + EF²
EF² = 1296
EF = √1296
EF = 36 units
Thus, the length of the EF in the right-angle triangle is 36 units if the length of DF is 15 units the length of DE is 39 units option (E) is correct.
Learn more about the right-angle triangle here:
brainly.com/question/3770177
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