PLEASE HELP
3. The function E(v)= 15v^2 / 2 models the
kinetic energy E in joules of an object
with a mass of 15 kilograms, where v is
the velocity of the object in meters per
second. Write the inverse function v(E) to
find the velocity of a 15-kilogram object
with kinetic energy E.

PLEASE HELP 3 The function Ev 15v2 2 models the kinetic energy E in joules of an object with a mass of 15 kilograms where v is the velocity of the object in met class=

Respuesta :

Answer:

i think it is 15v (E) = √(2E/m)

Step-by-step explanation:

From the question given:

E = ½mv²

E is the kinetic energy

m is the mass of object

v is the velocity.

To find a model v(E) for the velocity of the object, we simply make V the subject of the above equation.

This can be obtained as follow:

E = ½mv²

Cross multiply

mv² = 2E

Divide both side by m

v² = 2E/m

Take the square root of both side

v = √(2E/m)

Therefore, the model v(E) for the velocity of the object is given by:

v (E) = √(2E/m)

The inverse function v(E) to find the velocity of a 15-kilogram object

with kinetic energy E should be [tex]15v (E) = \sqrt (2E/m)[/tex]

Calculation of the inverse relation:

Since we know that

[tex]E = 1\div 2mv^2[/tex]

Here,

E is the kinetic energy

m is the mass of object

v is the velocity.

Now we can write like

[tex]mv^2 = 2E[/tex]

So,

[tex]v^2 = 2E/m[/tex]

Now Take the square root of both side

So,

[tex]v = \sqrt (2E/m)\\\\v (E) = \sqrt (2E/m)[/tex]

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