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a = ( 0 , 7 ) & b = ( 3 , 1 )
First need to find the slope using the following equation :
[tex]slope = \frac{y(b) - y(a)}{x(b) - x(a)} \\ [/tex]
[tex]slope = \frac{1 - 7}{3 - 0} \\ [/tex]
[tex]slope = \frac{ - 6}{3} \\ [/tex]
[tex]slope = - 2[/tex]
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We have following equation to find the point-slope form of the linear functions using the slope and one of the through points .
[tex]y - y(0) = m \times ( \: x - x(0) \: )[/tex]
[tex]x(0) = x - coordinate \: \: of \: \: through \: \: point \\ [/tex]
[tex]y(0) = y - coordinate \: \: of \: \: through \: \: point \\ [/tex]
[tex]m = slope[/tex]
I choose point (( a )) to put in the equation.
[tex]y - 7 = - 2 \times (x - 0)[/tex]
[tex]y - 7 = - 2x + 0[/tex]
[tex]y - 7 = - 2x[/tex]
Add sides 7
[tex]y - 7 + 7 = - 2x + 7[/tex]
[tex]y = - 2x + 7[/tex]
This the slope-intercept form .
Done...
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