Answer:
Step-by-step explanation:
These types of problems can be solved with substitution.
We just have to translate the word problem into math.
#1:
F = family, I = individual
[tex]F + I = 188\\95F + 42I = 12,507[/tex]
[tex]F = 188-I\\95(188-I) + 42I = 12507\\17860 - 95I + 42I = 12507\\-53I = -5353\\I = 101\\\\F + I = 188\\F + 101 = 188\\F = 87[/tex]
87 Families, 101 individuals
#2:
The perimeter is 899 meters. The perimeter can be defined as:
[tex]2L + 2W = P\\2L + 2W = 899[/tex]
We are also given that
[tex]2L = W - 100\\so\\2L + 2W = 899\\W- 100 + 2W = 899\\3W = 999\\W = 333\\\\L = \frac{W-100}{2} = \frac{333-100}{2} = \frac{233}{2}[/tex]
W = 333 meters, L = 233/2 meters
