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if two dice are rolled one time, find the probability of getting a sum less than or equal to 4 ​

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Answer:

The probability of getting a sum less than or equal to 4 ​is 1/6.

Step-by-step explanation:

When two dices are rolled, the number of outcomes are: 6*6 = 36 which is written in ordered pairs consisting of outcome of both dices.

When two dices are rolled, the number of sample space elements is:

[tex]n(S) = 36[/tex]

Let A be the event that the sum of outcomes is less than or equal to 4:

[tex]A = \{(1,1),(1,2),(1,3),(2,1),(2,2),(3,1)\}[/tex]

That implies

[tex]n(A) = 6[/tex]

The probability of getting sum less than or equal to 4 will be:

[tex]P(A) = \frac{n(A)}{n(S)} = \frac{6}{36} = \frac{1}{6}[/tex]

Hence,

The probability of getting a sum less than or equal to 4 ​is 1/6

Cricetus

The probability of getting a sum less than as well as equivalent to 4 will be "[tex]\frac{1}{6}[/tex]".

Probability:

The probability that may be an outcome will happen together in random experiment. The greater the likelihood of such an occurrence, the further probable it will materialize.

Let,

The event that the sum less than as well as equivalent to 4 be "A".

According to the question,

Whenever the 2 dices are rolled, the no. of outcomes will be:

= 6 × 6

= 36

and,

The no. of sample elements will be:

n(S) = 36

Now,

A = {(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)}

The probability be:

→ P(A) = [tex]\frac{n(A)}{n(S)}[/tex]

           = [tex]\frac{6}{36}[/tex]

           = [tex]\frac{1}{6}[/tex]

Thus the response above is correct.

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https://brainly.com/question/24756209