What is the effect on the graph of f(x) = x2 when it is transformed to
h(x) = 1/5x^2 +12?
O A. The graph of f(x) is horizontally compressed by a factor of 5 and
shifted 12 units up.
O B. The graph of f(x) is horizontally stretched by a factor of 5 and
shifted 12 units to the left.
C. The graph of f(x) is vertically compressed by a factor of 5 and
shifted 12 units up.
O D. The graph of f(x) is vertically compressed by a factor of 5 and
shifted 12 units to the left.
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The answer is A. when you compress horizontally you take it by a factor of 1/a. in this case a=5. 12 is your k value and k decides whether or not you shift up or down, because k is positive or is upward by 12

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RajarshiG RajarshiG · Answer 2 · 2022-06-08T12:49:09+02:00

As per transformation of graph, h(x) = ([tex]\frac{1}{5}[/tex])x² + 12 represents that the graph of f(x) is horizontally compressed by a factor of 5 and shifted up 12 units.

What is the transformation of a graph?

"Graph transformation is the process by which an existing graph, or graphed equation, is modified to produce a variation of the proceeding graph. It's a common type of problem in algebra, specifically the modification of algebraic equations.

Given, the graph is f(x) = x².

We know that, at the time of horizontally compressing a graph we need to multiply it by a factor of ([tex]\frac{1}{a}[/tex]).

Again, at the time of shifting a graph up we need to add a positive number of (b).

Therefore, a = 5 and b = 12.

Now, if we horizontally compress f(x) it by a factor of ([tex]\frac{1}{5}[/tex]) then it be ([tex]\frac{1}{5}[/tex])x².

Again, if we shifted up f(x) by 12 units, then it be ([tex]\frac{1}{5}[/tex])x² + 12.

Therefore, h(x) = ([tex]\frac{1}{5}[/tex])x² + 12 represents that the graph of f(x) is horizontally compressed by a factor of 5 and shifted 12 units up.

Learn more about the transformation of a graph here: https://brainly.com/question/10059147

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