If 52 J of heat is added to an aluminum can with a mass of 28.4 g , what is its temperature change? Specific heat capacity of aluminum is 0.903 J/g∘C.

Respuesta :

Q = mass x sph x temp change
temp change = Q/(mass x sph)
Temp change =57/(22 x .903)
Temp Change = 2.97 ∘C
Temp change 3.0 ∘C

We can use the heat equation,

Q = mcΔT


Where Q is the amount of energy transferred (J), m is the mass of the substance (g), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).


The given data

  Q = 52 J

  m = 28.4 g

   c = 0.903 J g⁻¹ °C⁻¹

 ΔT = ?


By applying the formula,

  52 J = 28.4 g x 0.903 J g⁻¹ °C⁻¹ x ΔT

    ΔT = 2.03 °C


Hence, the temperature change of aluminium during the heating process is 2.03 °C.