Using the greatest common factor for the terms, how can you write 12 + 90 as a product? A) 3(4 + 30) B) 4(3 + 15) C) 6(2 + 15) D) 12(1 + 8)
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SJ2006

(A) 3(4+30) Is the answer...






Ok, so we to find the biggest number that is divisible by 12 and 90.
Both 12 and 90 are divisible by 1, 2, 3, and 6.
So, the greatest number here is 6.

Hence, the answer is C. 6(2+15)